Equilibrium of Floating Bodies Questions and Answers

Equilibrium of Floating Bodies Questions and Answers Points : equilibrium of floating bodies short questions and answers Q1: Define the Archimede’s principle? Ans: The Archimede’s principle state “whenever a body is immersed wholly or partially in a fluid it is buoyed up by a force equal to the weight of fluid displaced by the body. Q:2 Define the term of buoyancy. Ans: The tendency of a fluid to uplift a submerged. Q:3 Define the term of center of buoyancy. Ans: The center of buoyancy is the center of area of the immersed section. Q:4: A uniform body 3m long, 2m wide and im deep floats in water. If the depth of immersion is 0.6 m what is the weight of body Ans: Weight of body = Wt of water & volume of immersed section
Volume = 1 x b x drowned depth
= 3 x 2 x 0.6 = 36m³
w.t of water = 9.81 KN/m³
Weight of body = 9.81 x 3.6 = 35.3 KN Q:5: Define Metacenter. Ans: Whenever a body floating in a liquid is given a small angular displacement, it starts oscillating about some point. This point, about which the body starts oscillating is called metacenter. Q:6: Define the metacenter height? Ans:The distance between the center of gravity of a floating body and the metacenter is called metacenter height. Q:7: Write the methods of determining metacentric height. Ans (1) Analytical Method
(2) Experimental Method Q.8: A rectangular pontoon of 5m long, 3m wide and 1.2 m deep Is immersed 0.8 m In sea water. If the density of sea water is 10KN/m³. Find the metacenter height of the pontoon?

Q.9: Write down the name of equilibrium of a floating body. Ans: (1) stable equilibrium
(2) unstable equilibrium
(3) Natural equilibrium neutral Q.10: Define the term of equilibrium. Ans: A body is said to be in a neutral equilibrium if it occupies a new position and remains at rest in this new position when given a small angular displacement.